学习中……

PROBLEMS
char** t;
const char** t1 = t;//invalid conversion from char** to const char**. but WHY?

//A workaround
char** t;
const char* t2 = *t;//Convert to const char* first.
const char** t1 = &t2;//OK, here, but WHY?


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引用
1. http://www.cnblogs.com/chenleiustc/archive/2011/04/09/2010647.html